Answer
$|\textbf{d}_{s}|=565\,km$
$|\textbf{d}_{w}|=396\,km$
Work Step by Step
Displacement $d=velocity\times time=230\,km/h(in\,the\,direction\,S\,35^{\circ}W)\times3\,h$$=690\,km$ in the direction S $35^{\circ}$ W.
Magnitude of the component of the displacement vector along the south is given by
$|\textbf{d}_{s}|=|\textbf{d}|\cos\theta=690\,km\times \cos 35^{\circ}=565\,km$
Distance travelled in the west direction is
$|\textbf{d}_{w}|=|\textbf{d}|\sin35^{\circ}=690\,km\times\sin35^{\circ}=396\,km$
