Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.4 - Introduction to Identities - 1.4 Problem Set - Page 40: 38

Answer

$\sin\theta$ = $\frac{\sqrt 3}{2}$

Work Step by Step

We know from first Pythagorean identity that- $\sin\theta$ = ± $\sqrt (1-\cos^{2}\theta)$ As $\theta$ terminates in Q II, Therefore $\sin\theta$ will be positive- $\sin\theta$ = $\sqrt (1-\cos^{2}\theta)$ substitute the given value of $\cos\theta$- $\sin\theta$ = $\sqrt (1-(\frac{-1}{2})^{2})$ $\sin\theta$ = $\sqrt (1-\frac{1}{4})$ $\sin\theta$ = $\sqrt (\frac{4-1}{4})$ = $\sqrt (\frac{3}{4})$ $\sin\theta$ = $\frac{\sqrt 3}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.