Answer
$y = \pm 12 $
Work Step by Step
$\cos{\theta} = \dfrac{x}{r} = \dfrac{5}{13}$
$\therefore x = 5 \hspace{20pt} r = 13$
$r^2 = x^2+y^2 \\ y^2 = r^2 - x^2 \\ y = \pm \sqrt{r^2-x^2} \\ = \pm \sqrt{(13)^2-(5)^2}$
$\boxed{y = \pm 12}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 1 - Section 1.3 - Definition I: Trigonometric Functions - 1.3 Problem Set - Page 33: 75
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