Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.2 - The Rectangular Coordinate System - 1.2 Problem Set - Page 24: 30

Answer

At $x_{1}, y_{1}$ is approximately 36.56 feet. At $x_{2}, y_{2}$ is approximately 14.06 feet. See graph:

Work Step by Step

$y=-\frac{3}{320}(x-80)^2+60$ $y_{1}=\frac{3}{320}(30-80)^2+60$ $y_{1}\approx 36.56 feet$ $y_{2}=\frac{3}{320}(150-80)^2+60$ $y_{2}\approx 14.06 feet$
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