Answer
$0-\frac{5}{9}i$
Work Step by Step
$\frac{5}{9i}=\frac{5}{9i}(\frac{-i}{-i})=\frac{5\times -i}{9i\times -i}=\frac{-5i}{-9i^{2}}=\frac{-5i}{-9(-1)}=\frac{-5i}{9}=-\frac{5}{9}i=0-\frac{5}{9}i$
We know that $i^{2}=-1$.
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