Answer
$0-\frac{2}{3}i$
Work Step by Step
$\frac{2}{3i}=\frac{2}{3i}(\frac{-i}{-i})=\frac{2\times -i}{3i\times -i}=\frac{-2i}{-3i^{2}}=\frac{-2i}{-3(-1)}=\frac{-2i}{3}=-\frac{2}{3}i=0-\frac{2}{3}i$
We know that $i^{2}=-1$.
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