Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 358: 90

Answer

$0+12i$

Work Step by Step

$\frac{12}{-i}=\frac{12}{-i}(\frac{i}{i})=\frac{12\times i}{-i\times i}=\frac{12i}{-i^{2}}=\frac{12i}{-(-1)}=\frac{12i}{1}=12i=0+12i$ We know that $i^{2}=-1$.
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