Answer
$0+12i$
Work Step by Step
$\frac{12}{-i}=\frac{12}{-i}(\frac{i}{i})=\frac{12\times i}{-i\times i}=\frac{12i}{-i^{2}}=\frac{12i}{-(-1)}=\frac{12i}{1}=12i=0+12i$
We know that $i^{2}=-1$.
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