Answer
$9i+12$
Work Step by Step
Step 1: $3i(2-i)(2-i)$
Step 2: $3i(2(2-i)-i(2-i))$
Step 3: $3i(4-2i-2i+i^{2})$
Step 4: $3i(4-4i+(-1))$
Step 5: $3i(4-4i-1)$
Step 6: $3i(3-4i)$
Step 7: $9i-12i^{2}$
Step 8: $9i-12(-1)$
Step 9: $9i+12$