Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 357: 44

Answer

$i\sqrt 2$

Work Step by Step

$\frac{\sqrt -54}{\sqrt 27}=\frac{i\sqrt 54}{\sqrt 27}=i\times\frac{\sqrt 54}{\sqrt 27}=i\times\sqrt \frac{54}{27}=i\times\sqrt 2=i\sqrt 2$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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