Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 357: 38

Answer

-17

Work Step by Step

$\sqrt -17\times\sqrt -17=\sqrt (-1\times17)\times\sqrt (-1\times17)=\sqrt -1\times\sqrt 17\times\sqrt -1\times\sqrt 17=i\times i\times\sqrt 17\times\sqrt 17=i^{2}\times(\sqrt 17)^{2}=-1\times17=-17$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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