Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 357: 27

Answer

$x=±2i\sqrt 3$

Work Step by Step

$x^{2}+12=0$ $x^{2}=-12$ $x=±\sqrt -12$ $x=±(\sqrt 4\times\sqrt 3\times\sqrt -1)$ $x=±2i\sqrt 3$ We know that $\sqrt 4=2$, because $2^{2}=4$. We know that $\sqrt -1=i$, because $-1^{2}=i$.
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