Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 7 - Review Exercises - Page 344: 30

Answer

$C = 77.1^{\circ}$

Work Step by Step

We can use the law of cosines to find $C$: $AB^2 = AC^2+BC^2-2(AC)(BC)~cos~C$ $2(AC)(BC)~cos~C = AC^2+BC^2-AB^2$ $cos~C = \frac{AC^2+BC^2-AB^2}{2(AC)(BC)}$ $C = arccos(\frac{AC^2+BC^2-AB^2}{2(AC)(BC)})$ $C = arccos(\frac{102^2+135^2-150^2}{2(102)(135)})$ $C = arccos(0.2225)$ $C = 77.1^{\circ}$
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