Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 Applications of Vectors - 7.5 Exercises - Page 338: 30b

Answer

The magnitude of $v$ is 87 mi/s

Work Step by Step

$v_r = 67~mi/s$ $v_t = 55.64~mi/s$ We can find the magnitude of $v$: $v = \sqrt{v_r^2+v_t^2}$ $v = \sqrt{(67~mi/s)^2+(55.64~mi/s)^2}$ $v = 87~mi/s$ The magnitude of $v$ is 87 mi/s
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