Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Test - Page 288: 18b

Answer

$x = arctan(\frac{3}{y-4})$

Work Step by Step

$y = 4+ 3~cot~x$, where $x~in~(0,\pi)$ $3~cot~x = y-4$ $cot~x = \frac{y-4}{3}$ $tan~x = \frac{3}{y-4}$ $x = arctan(\frac{3}{y-4})$
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