Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Test - Page 287: 6

Answer

There is no angle $\theta$ such that $sin~\theta = 3$ Therefore, $sin^{-1}~3$ is not defined

Work Step by Step

Let $\theta = sin^{-1}~3$ Then: $sin~\theta = 3$ However: $-1 \leq sin~\theta \leq~1$, for all angles $\theta$ There is no angle $\theta$ such that $sin~\theta = 3$ Therefore, $sin^{-1}~3$ is not defined
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