Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.2 Trigonometric Equations I - 6.2 Exercises - Page 267: 16

Answer

No solution.

Work Step by Step

$\sec^2 x + 2= -1$ $(\sec x)(\sec x) = -\frac{1}{2}$ $(\frac{1}{\cos x})(\frac{1}{\cos x}) = -\frac{1}{2}$ $(\frac{1}{\cos^2 x}) = -\frac{1}{2}$ $1 = -\frac{\cos^2 x}{2}$ $-2 = \cos^2 x$ No solution.
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