Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.2 Trigonometric Equations I - 6.2 Exercises - Page 266: 3

Answer

1) Given equation seems to be quadratic, but constant term is not present hence it can be converted to linear by dividing both the sides by $\sec x$. 2) Only one trigonometric function i.e. $\sec x$ is present. 3) Equation must be solved for $\sec x$ first. 3) Now equation can be solved for $x$.

Work Step by Step

Given equation is- $5 \sec^{2} x$ = $6 \sec x$ Steps to be taken- 1) Given equation seems to be quadratic, but constant term is not present hence it can be converted to linear by dividing both the sides by $\sec x$. 2) Only one trigonometric function i.e. $\sec x$ is present. 3) Equation must be solved for $\sec x$ first. 3) Now equation can be solved for $x$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.