Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.1 Inverse Circular Functions - 6.1 Exercises - Page 258: 34

Answer

$\sec^{-1}0$ is not defined.

Work Step by Step

Inverse Secant Function: $y=\sec^{-1}x$ or $y=$ arcsec $x$ means that $x=\sec y$, for $0 \leq y \leq \pi, y\displaystyle \neq\frac{\pi}{2}$. ---------------- The secant function is reciprocal to the cosine. There is no y from the interval $0 \leq y \leq \pi, y\displaystyle \neq\frac{\pi}{2}$ such that $\displaystyle \sec y=\frac{1}{\cos y}=0$ (the reciprocal of 0 does not exist) So, $\sec^{-1}0$ is not defined.
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