Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Trigonometric Identities - Section 5.4 Sum and Difference Identities for Sine and Tangent - 5.4 Exercises - Page 221: 32

Answer

$sin(45^{\circ}+\theta) = \frac{\sqrt{2}}{2}~(cos~\theta+ sin~\theta)$

Work Step by Step

$sin(45^{\circ}+\theta) = sin(45^{\circ})~cos~\theta+ cos(45^{\circ})~sin~\theta$ $sin(45^{\circ}+\theta) = \frac{\sqrt{2}}{2}~cos~\theta+ \frac{\sqrt{2}}{2}~sin~\theta$ $sin(45^{\circ}+\theta) = \frac{\sqrt{2}}{2}~(cos~\theta+ sin~\theta)$
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