Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Trigonometric Identities - Section 5.2 Verifying Trigonometric Identities - 5.2 Exercises - Page 204: 84

Answer

The following statement is an identity: $1+cot^2~x = \frac{sec^2~x}{sec^2~x-1}$

Work Step by Step

We can see that the graph of $~~y = 1+cot^2~x~~$ is the same as the graph of $~~y = \frac{sec^2~x}{sec^2~x-1}$ Therefore, the following statement is an identity: $1+cot^2~x = \frac{sec^2~x}{sec^2~x-1}$
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