Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Trigonometric Identities - Section 5.2 Verifying Trigonometric Identities - 5.2 Exercises - Page 202: 17

Answer

$$2\sin^2 x+3\sin x+1=(\sin x+1)(2\sin x+1)$$

Work Step by Step

$$A=2\sin^2 x+3\sin x+1$$ We would separate $3\sin x$ into $2\sin x$ and $\sin x$. $$A=(2\sin^2 x+2\sin x)+(\sin x+1)$$ $$A=2\sin x(\sin x+1)+(\sin x+1)$$ $$A=(\sin x+1)(2\sin x+1)$$
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