Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Trigonometric Identities - Section 5.2 Verifying Trigonometric Identities - 5.2 Exercises - Page 202: 14

Answer

$$\sec^2\theta-1=(\sec\theta-1)(\sec\theta+1)$$

Work Step by Step

$$A=\sec^2\theta-1$$ We factor the expression like normal, using $$a^2-b^2=(a-b)(a+b)$$ Therefore, $$A=(\sec\theta-1)(\sec\theta+1)$$
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