Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Test - Page 244: 8d

Answer

Since $sin(A+B)$ is positive and $cos(A+B)$ is negative, the quadrant of $A+B$ must be quadrant II.

Work Step by Step

$sin(A+B) = \frac{33}{65}$ $cos(A+B) = -\frac{56}{65}$ Since $sin(A+B)$ is positive and $cos(A+B)$ is negative, the quadrant of $A+B$ must be quadrant II.
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