Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Review Exercises - Page 243: 52

Answer

$\frac{sin~2x}{sin~x} = \frac{2}{sec~x}$

Work Step by Step

$\frac{sin~2x}{sin~x} = \frac{2~sin~x~cos~x}{sin~x}$ $\frac{sin~2x}{sin~x} = \frac{2~cos~x}{1}$ $\frac{sin~2x}{sin~x} = \frac{2}{\frac{1}{cos~x}}$ $\frac{sin~2x}{sin~x} = \frac{2}{sec~x}$
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