Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Review Exercises - Page 242: 8

Answer

$$\frac{\cot\theta}{\sec\theta}=\frac{\cos^2\theta}{\sin\theta}$$

Work Step by Step

$$A=\frac{\cot\theta}{\sec\theta}$$ We need to rewrite $\cot\theta$ and $\sec\theta$ in terms of $\sin\theta$ and $\cos\theta$, using the following identities $$\cot\theta=\frac{\cos\theta}{\sin\theta}\hspace{2cm}\sec\theta=\frac{1}{\cos\theta}$$ $$A=\frac{\frac{\cos\theta}{\sin\theta}}{\frac{1}{\cos\theta}}$$ $$A=\frac{\cos\theta\times\cos\theta}{\sin\theta\times1}$$ $$A=\frac{\cos^2\theta}{\sin\theta}$$ It could not be simplified to any simpler form, so we stop here.
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