Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Review Exercises - Page 242: 19

Answer

$$\tan(-35^\circ)=\cot125^\circ$$ 19 is matched with H.

Work Step by Step

$$\tan(-35^\circ)$$ We know that $125^\circ-35^\circ=90^\circ$. Now remind yourself of Cofunction Identity for tangent and cotangents, which state $$\tan\theta=\cot(90^\circ-\theta)$$ Thus, $$\tan(-35^\circ)=\cot[90^\circ-(-35^\circ)]$$ $$\tan(-35^\circ)=\cot(90^\circ+35^\circ)$$ $$\tan(-35^\circ)=\cot125^\circ$$ which corresponds to choice H. Thus, 19 is matched with H.
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