Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Quiz (Sections 5.1-5.4) - Page 224: 5c

Answer

Angle $(A+B)$ lies in quadrant III.

Work Step by Step

Take a look back the results in 2 previous parts: $$\sin(A+B)=-\frac{63}{65}$$ and $$\cos(A+B)=-\frac{16}{65}$$ Both $\sin(A+B)$ and $\cos(A+B)$ are negative, so angle $(A+B)$ must lie in quadrant III.
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