Answer
The amplitude is $\frac{1}{2}$
The period is $\pi$
The vertical translation is 0
The phase shift is $\frac{\pi}{8}$
Work Step by Step
$y = A~csc(Bx+C)+D$
$y = \frac{1}{2}csc(2x-\frac{\pi}{4})$
$A = \frac{1}{2}$
$B = 2$
$C = -\frac{\pi}{4}$
$D = 0$
$\vert A \vert$ is the amplitude.
The amplitude is $\frac{1}{2}$
$\frac{2\pi}{B}$ is the period.
The period is $\pi$
$D$ is the vertical translation.
The vertical translation is 0
$\frac{-C}{B}$ is the phase shift.
The phase shift is $\frac{\pi}{8}$