Answer
The amplitude is 1
The period is $2\pi$
The vertical translation is 0
The phase shift is $\frac{3\pi}{4}$
Work Step by Step
$y = A~sin(Bx+C)+D$
$y = -sin(x-\frac{3\pi}{4})$
$A = -1$
$B = 1$
$C = -\frac{3\pi}{4}$
$D = 0$
$\vert A \vert$ is the amplitude.
The amplitude is 1
$\frac{2\pi}{B}$ is the period.
The period is $2\pi$
$D$ is the vertical translation.
The vertical translation is 0
$\frac{-C}{B}$ is the phase shift.
The phase shift is $\frac{3\pi}{4}$