Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Quiz (Sections 4.1-4.2) - Page 159: 7

Answer

$y = -1+\frac{1}{2}sin~x$ We can see the graph below. The period is $2\pi$ The amplitude is $0.5$

Work Step by Step

$y = -1+\frac{1}{2}sin~x$ When $x = 0$, then $y = -1+\frac{1}{2}sin~0 = -1$ When $x = \frac{\pi}{2}$, then $y = -1+\frac{1}{2}sin ~\frac{\pi}{2} = -0.5$ When $x = \pi$, then $y = -1+\frac{1}{2}sin~\pi = -1$ When $x = \frac{3\pi}{2}$, then $y = -1+\frac{1}{2}sin~\frac{3\pi}{2} = -1.5$ When $x = 2\pi$, then $y = -1+\frac{1}{2}sin~2\pi = -1$ We can see the graph below. The period is $2\pi$ The amplitude is $0.5$
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