Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.5 Harmonic Motion - 4.5 Exercises - Page 179: 4b

Answer

$s(1) = -2$ The object is moving downward at time $t=1$.

Work Step by Step

$s(t) = -4~cos~\frac{5\pi}{3} t$ When $t = 1$: $s(1) = -4~cos~[\frac{5\pi}{3} (1)] = -4(0.5) = -2$ On the graph, we can see that the slope of the graph is negative at time $t = 1$. Therefore, the object is moving downward at time $t=1$.
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