Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.3 Graphs of the Tangent and Cotangent Functions - 4.3 Exercises - Page 168: 47d

Answer

$d=12.3$ m

Work Step by Step

We substitute $t=1.2$ in the equation and then solve for $d$: $d=4\tan 2\pi t$ $d=4\tan 2\pi (1.2)$ $d=4\tan (2\pi \times1.2)$ $d=4\tan 2.4\pi$ Since $\tan 2.4\pi=3.07768$; $d=4\tan 2.4\pi$ $d=4(3.07768)$ $d=12.311\approx12.3$ Therefore, for $t=1.2$ seconds, $d=12.3$ m.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.