Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.3 Graphs of the Tangent and Cotangent Functions - 4.3 Exercises - Page 166: 1

Answer

C

Work Step by Step

The function is $y=-\tan x$. In the general equation $y=a\tan bx$, when $a\lt0$, the graph is reflected across the x-axis. In addition, comparing $y=-\tan x$ to $y=a\tan bx$, we find that $b=1$. The value of $b$ can be used to find the location of the two vertical asymptotes: $bx=-\frac{\pi}{2}$ and $bx=\frac{\pi}{2}$ $1x=-\frac{\pi}{2}$ and $1x=\frac{\pi}{2}$ $x=-\frac{\pi}{2}$ and $x=\frac{\pi}{2}$ The location of the asymptotes is the same as that of the graph of $\tan x$. Therefore, using this information, we can ascertain that the graph of $y=-\tan x$ will be the same as the graph of $y=-\tan x$ except that it will be reflected across the x-axis. This means that the correct graph for $y=-\tan x$ is C.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.