Answer
D
Work Step by Step
We first write the equation in the form $y=a \cos [b(x-d)]$. Therefore, $y=2\sin (3x-4)$ becomes $y=2\sin [3(x-\frac{4}{3})]$.
Comparing the two equations, $a=2,b=3$ and $d=\frac{4}{3}$.
The amplitude is $|a|=|2|=2.$
The period is $\frac{2\pi}{b}=\frac{2\pi}{3}$.
The phase shift is $|d|=|\frac{4}{3}|=\frac{4}{3}.$
Therefore, the description in option D is the correct answer.