Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.1 Graphs of the Sine and Cosine Functions - 4.1 Exercises - Page 146: 56c

Answer

For $t = 0.02$, $E=-3.074$ For $t = 0.04$, $E=1.174$ For $t = 0.08$, $E=-3.074$ For $t = 0.12$, $E=-3.074$ For $t = 0.14$, $E=1.174$

Work Step by Step

We substitute each of the five values of $t$ in the formula to find the value of E for each value of $t$: For $t = 0.02$, $E=3.8 \cos 40\pi(0.02)=3.8\cos 0.8\pi=3.8(-0.8090)=-3.074$ For $t = 0.04$, $E=3.8 \cos 40\pi(0.04)=3.8\cos 1.6\pi=3.8(0.3090)=1.174$ For $t = 0.08$, $E=3.8 \cos 40\pi(0.08)=3.8\cos 3.2\pi=3.8(-0.8090)=-3.074$ For $t = 0.12$, $E=3.8 \cos 40\pi(0.12)=3.8\cos 4.8\pi=3.8(-0.8090)=-3.074$ For $t = 0.14$, $E=3.8 \cos 40\pi(0.14)=3.8\cos 5.6\pi=3.8(0.3090)=1.174$
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