Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.1 Graphs of the Sine and Cosine Functions - 4.1 Exercises: 5

Answer

B

Work Step by Step

Using the formula $\frac{2\pi}{b}$, we find that the period of $y=\sin 2x$ is: $\frac{2\pi}{b}=\frac{2\pi}{2}=\pi$ In addition, the formula $y=\sin 2x$ stipulates that the amplitude of the function is 1. Therefore, we need to find a sin wave whose amplitude is 1 and whose period is $\pi$. We find that graph of option B is the correct answer in this regard.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.