Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.1 Graphs of the Sine and Cosine Functions - 4.1 Exercises - Page 143: 5

Answer

B

Work Step by Step

Using the formula $\frac{2\pi}{b}$, we find that the period of $y=\sin 2x$ is: $\frac{2\pi}{b}=\frac{2\pi}{2}=\pi$ In addition, the formula $y=\sin 2x$ stipulates that the amplitude of the function is 1. Therefore, we need to find a sin wave whose amplitude is 1 and whose period is $\pi$. We find that graph of option B is the correct answer in this regard.
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