Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Review Exercises - Page 130: 63

Answer

The linear speed of a point on the edge of the flywheel is 39.6 m/s

Work Step by Step

The flywheel rotates through an angle of $2\pi$ radians 90 times each second. We can find the angular speed of the flywheel: $\omega = \frac{\theta}{t}$ $\omega = \frac{(2\pi~rad)(90)}{1~s}$ $\omega = (180~\pi)~rad/s$ We can find the linear speed of a point on the edge of the flywheel: $v = \omega ~r$ $v = (180~\pi~rad/s)(7~cm)$ $v = 3960~cm/s$ $v = 39.6~m/s$ The linear speed of a point on the edge of the flywheel is 39.6 m/s
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