Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.4 Linear and Angular Speed - 3.4 Exercises - Page 125: 32

Answer

The linear speed of the tip is $~~(\frac{14~\pi}{15})~mm/s~~$ which is $~~2.93~mm/s$

Work Step by Step

The second hand of a clock moves through an angle of $2\pi$ radians in a time of 60 seconds. We can find the angular speed: $\omega = \frac{\theta}{t}$ $\omega = \frac{2\pi~rad}{60~s}$ $\omega = \frac{\pi}{30}~rad/s$ We can find the linear speed of the tip: $v = \omega~r$ $v = (\frac{\pi}{30}~rad/s)(28~mm)$ $v = (\frac{28~\pi}{30})~mm/s$ $v = (\frac{14~\pi}{15})~mm/s = 2.93~mm/s$ The linear speed of the tip is $~~(\frac{14~\pi}{15})~mm/s~~$ which is $~~2.93~mm/s$
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