Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.3 The Unit Circle and Circular Functions - 3.3 Exercises - Page 119: 86e

Answer

$48.3^{\circ}$ F

Work Step by Step

Since September $1$ is Day $244$, we substitute $x=244$ into the following equation and solve using a calculator: $T(x)=37\sin[\frac{2\pi}{365}(x-101)]+25$ $T(x)=37\sin[\frac{2\pi}{365}(244-101)]+25$ $T(x)=37\sin[\frac{2\pi}{365}(143)]+25$ $T(x)=37\sin[2.462]+25$ $T(x)=37(0.6285)+25$ $T(x)=23.25+25$ $T(x)=48.25\approx48.3^{\circ}$ F
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