Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.3 The Unit Circle and Circular Functions - 3.3 Exercises - Page 117: 3

Answer

(a) $\sin{2\pi}=0$ (b) $\cos{2\pi}=1$ (c) $\tan{2\pi}=0$

Work Step by Step

RECALL: $\sin{s} = y \\\cos{s} = x \\\tan{s} = \frac{y}{x}$ The angle $2\pi$ will intersect the unit circle at the point $(1, 0)$ (refer to Figure 15 on page 113). The point $(1, 0)$ has: $x=1 \\y=0$ Thus, $\sin{2\pi}=0 \\\cos{2\pi}=1 \\\tan{2\pi}=\frac{0}{1} = 0$
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