Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Test: 1

Answer

sin A = $\frac{12}{13}$ csc A = $\frac{13}{12}$ cos A = $\frac{5}{13}$ sec A = $\frac{13}{5}$ tan A = $\frac{5}{12}$ cot A = $\frac{12}{5}$

Work Step by Step

sin A = $\frac{perpendicular}{hypotenuse}$ csc A = $\frac{hypotenuse}{perpendicular}$ cos A = $\frac{base}{hypotenuse}$ sec A = $\frac{hypotenuse}{base}$ tan A = $\frac{perpendicular}{base}$ cot A = $\frac{base}{perpendicular}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.