## Trigonometry (10th Edition)

Published by Pearson

# Chapter 2 - Test: 1

#### Answer

sin A = $\frac{12}{13}$ csc A = $\frac{13}{12}$ cos A = $\frac{5}{13}$ sec A = $\frac{13}{5}$ tan A = $\frac{5}{12}$ cot A = $\frac{12}{5}$

#### Work Step by Step

sin A = $\frac{perpendicular}{hypotenuse}$ csc A = $\frac{hypotenuse}{perpendicular}$ cos A = $\frac{base}{hypotenuse}$ sec A = $\frac{hypotenuse}{base}$ tan A = $\frac{perpendicular}{base}$ cot A = $\frac{base}{perpendicular}$

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