Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Review Exercises - Page 91: 65a

Answer

$h = 716~mi$

Work Step by Step

$h = R~(\frac{1}{cos~\frac{180~T}{P}}-1)$ We can find $h$ when $T = 25~min$ and $P = 140~min$: $h = R~(\frac{1}{cos~\frac{180~T}{P}}-1)$ $h = (3955~mi)~(\frac{1}{cos~\frac{(180)(25~min)}{140~min}}-1)$ $h = 716~mi$
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