Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Review Exercises - Page 88: 9

Answer

True

Work Step by Step

$\tan 60^{\circ}\geq \cot 40^{\circ}$ $\cot 40^{\circ} = \tan (90^{\circ} - 40^{\circ}) = \tan 50^{\circ}$ for $0\leq\theta\leq90^{\circ}$ as angle increase, value of tangent increase , therefore $\tan 60^{\circ}\gt \tan 50^{\circ}$
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