Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 84: 41a

Answer

$d = 323~ft$

Work Step by Step

We can find the distance $d$ between $P$ and $Q$: $\frac{d}{R} = tan~\frac{\theta}{2}$ $d = (R)~tan~\frac{\theta}{2}$ $d = (965~ft)~tan~(\frac{37^{\circ}}{2})$ $d = 323~ft$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.