Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 84: 39

Answer

The minimum distance is 10.8 feet

Work Step by Step

We can convert the angle to degrees: $\theta = 23^{\circ}20' = (23+\frac{20}{60})^{\circ} = 23.3^{\circ}$ We can find the minimum distance $x$: $\frac{4.65~ft}{x} = tan(23.3^{\circ})$ $x = \frac{4.65~ft}{tan(23.3^{\circ})}$ $x = 10.8~ft$ The minimum distance is 10.8 feet
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