Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 82: 22

Answer

2.0 mi

Work Step by Step

$\angle B = 90^{\circ} -53^{\circ} 40' = 36^{\circ} 20$ $\cos (36^{\circ} 20') = \frac{x}{2.5}$ $x \approx 2.0 mi$
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