Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 82: 19

Answer

2202.6 ft

Work Step by Step

$\angle A = 90 ^{\circ} -58^{\circ} 22' = 31^{\circ} 38'$ $AB = 2587 ft$ [in a right-angles trinagle] Apply cosine definition $\cos (31^{\circ} 38') =\frac{x}{2587} $ $x\approx 2202.6 ft$
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