## Trigonometry (10th Edition)

Published by Pearson

# Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 62

#### Answer

$P$ = -5$\sqrt2$,-5$\sqrt2$)

#### Work Step by Step

The Point $P$ is represented by the coordinate ($x$,$y$). $\cos$ $\theta$ = $\frac{x}{r}$ $\cos$ 225$^{\circ}$ = $\frac{x}{10}$ x = 10 $\cos$ 225$^{\circ}$ x = 10(-$\frac{\sqrt2}{2}$) x = -5$\sqrt2$ $\sin$ $\theta$ = $\frac{y}{r}$ $\sin$ 225$^{\circ}$ = $\frac{y}{10}$ y = 10 $\sin$ 225$^{\circ}$ y = 20(-$\frac{\sqrt2}{2}$) y = -5$\sqrt2$ Therefore: $P$ = -5$\sqrt2$,-5$\sqrt2$)

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.