Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 62

Answer

$P$ = -5$\sqrt2$,-5$\sqrt2$)
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Work Step by Step

The Point $P$ is represented by the coordinate ($x$,$y$). $\cos$ $\theta$ = $\frac{x}{r}$ $\cos$ 225$^{\circ}$ = $\frac{x}{10}$ x = 10 $\cos$ 225$^{\circ}$ x = 10(-$\frac{\sqrt2}{2}$) x = -5$\sqrt2$ $\sin$ $\theta$ = $\frac{y}{r}$ $\sin$ 225$^{\circ}$ = $\frac{y}{10}$ y = 10 $\sin$ 225$^{\circ}$ y = 20(-$\frac{\sqrt2}{2}$) y = -5$\sqrt2$ Therefore: $P$ = -5$\sqrt2$,-5$\sqrt2$)
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