Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 49

Answer

$\sin$$^{2}$ 225$^{\circ}$ - $\cos$$^{2}$ 270$^{\circ}$ + $\tan$$^{2}$ 60$^{\circ}$ = $\frac{7}{2}$

Work Step by Step

$\sin$$^{2}$ 225$^{\circ}$ - $\cos$$^{2}$ 270$^{\circ}$ + $\tan$$^{2}$ 60$^{\circ}$ $\sin$ 225$^{\circ}$ = $\frac{-1}{\sqrt2}$ $\cos$270$^{\circ}$ = 0 $\tan$ 60$^{\circ}$ = $\sqrt3$ Therefore: = ($\frac{1}{\sqrt2}$)$^{2}$ - 0 + ($\sqrt3$)$^{2}$ = $\frac{1}{2}$ + 3 = $\frac{1 + 6}{2}$ = $\frac{7}{2}$ $\sin$$^{2}$ 225$^{\circ}$ - $\cos$$^{2}$ 270$^{\circ}$ + $\tan$$^{2}$ 60$^{\circ}$ = $\frac{7}{2}$
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