Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises: 48

Answer

$\cot$$^{2}$ 135$^{\circ}$ - $\sin$ 30$^{\circ}$ + 4($\tan$ 45$^{\circ}$) = $\frac{9}{2}$

Work Step by Step

$\cot$$^{2}$ 135$^{\circ}$ - $\sin$ 30$^{\circ}$ + 4($\tan$ 45$^{\circ}$) $\cot$ 135$^{\circ}$ = $\cot$ 45$^{\circ}$(In Quadrant II) = -1 $\sin$ 30$^{\circ}$ = $\frac{1}{2}$ $\tan$ 45$^{\circ}$ = 1 Therefore: = (-1)$^{2}$ - $\frac{1}{2}$ + 4 = 1 - $\frac{1}{2}$ + 4 = $\frac{2 - 1 + 8}{2}$ = $\frac{9}{2}$ $\cot$$^{2}$ 135$^{\circ}$ - $\sin$ 30$^{\circ}$ + 4($\tan$ 45$^{\circ}$) = $\frac{9}{2}$
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